【人気ダウンロード！】 (a-b)^3+(b-c)^3+(c-a)^3= 618010-A+b+c=1 a^3+b^3+c^3=1
Now divide the two aspects via 3 so as that b may well be via itself on the left area Now the equation is b= (c5a)/(3) 8 x/y = w to remedy for x, lower back, you ought to hold all of the different words (y, w) to the different area(abc) 3 a 3 b 3 c 3 We can choose three "a"'s for the cube in one way C(3,3)=1, or we can choose an a from the first factor and one from the second and one from the third, being the only way to make a3 The coefficient of the cubes is therefore 1 (It's the same for a, b and c, of course) 3a 2 b3a 2 c Next, we consider the a 2 terms WeExample Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3 Pdf 100 Inequalities Problems Amir Parvardi Academia Edu A+b+c=1 a^3+b...